Day 2: Clever Stuff Python Challenge
![Clever Stuff Python Challenge. What would the output of this code be? Extra points if you can identify the bug in this code. The code defines list_to_dict(items, output={}), documented as 'Convert a list of key value pairs to dictionary': for each item it sets output[item[0]] = item[1], then returns output. It sets products to [['stuffing', 3.75], ['wrapping paper', 0.65], ['mince pies', 2.99]] and calls products_dict = list_to_dict(products). It sets users to [['rudolf', 20], ['dasher', 8], ['prancer', 19]] and calls users_dict = list_to_dict(users). Finally it prints products_dict and then users_dict.](/_astro/slide-1.C1cxYaqG_1HwWes.png)
Reveal the answer
Both lines print the same dictionary: {'stuffing': 3.75, 'wrapping paper': 0.65, 'mince pies': 2.99, 'rudolf': 20, 'dasher': 8, 'prancer': 19} The bug: the default value output={} is created once, when the function is defined, so every call that doesn't pass its own output shares and adds to the same dictionary. Use output=None and create a new dictionary inside the function instead.